SYLLABUS

(Click the Topic to Explore)

 

  • Types of reasoning
  • Number series, Letter series, Codes and Relationships.
  • Mathematical Aptitude (Fraction, Time & Distance, Ratio, Proportion and Percentage, Profit and Loss, Interest and Discounting, Averages etc.).

Mathematical Reasoning is the easiest if you are from Mathematics background and if you are not, it depends on your thought process and your willingness to accurately attempt the questions in this section. The Mathematical Reasoning questions in the online format has become easier than those when in the paper format.

For the candidates not from Mathematical background, the questions are not tough, therefore, as much as you practice, the questions will become easier. It is a request that in the name of preparation, do not attempt or practice the past year questions (only), start with basics, even though it will mean for you to catch up with or revisit  the Mathematics concepts and formulas from class 5th to  Series formulas from class 9th or 10th.

Average, Coding, unitary method, Equations, Ratio and Mixture, Time, and Distance, Average and Percentage; these are some of the important topics to be revised and prepared for the NTA NET Exam.

It took a lot of time to correctly articulate and have a complete article on this particular module for preparation and to admit this was the most difficult but still incomplete in a certain way because one cannot include all the practice questions and all the topics in one article. With proper thoughts we are including formulas for every topic and some of the questions from past years along with their solutions. So, if you feel any topic is missing, just send us an email with the topic and details required and the topic will be added and emailed you too.

 

So, let’s start this.

Number Series & Letter Series: In order to solve a Series question , one needs to establish a common and consistent relationship between the terms; this relationship can be of one generation or multiple generations; meaning – one level relationship or multiple level relationships. Usually NET exam has easier level of questions than other competitive exams but still one needs to practice because each question needs to be solved within a minute with accuracy. It is better to practice all the types pf series starting with basics and then it will be safe to practice past year questions.

 TYPE – 1

 Q1. 14,21,29,38,48, 59, ?

  1. 69
  2. 79
  3. 81
  4. 75
  5. 71  

  Sol.  14 (+7) 21  (+8)  29 (+9)  38(+10)  48 (+11)  59 (+12)  71

   It is a linear progressive, the pattern can be observed with an addition of +1 in the difference, thus, the answer is 71 (e).

 Q2. 5,9,17,29, 45,?

  1. 60
  2. 65
  3. 68
  4. 70
  5. None of these

  Sol. 5 (+4),9 (+4+4), 17 (+4+4+4),29 (+4+4+4+4),45 (+4+4+4+4+4),65

      It is a progression with a combination of addition and multiplication, i.e.  multiple operatives in a single series, not to worry, more and more one practices, the                        patterns will be easily visible, Here, the answer is (b). The increase in addition of 4s, can also be multiplication of 4s.

Q3.

 

 

 

  1. 14
  2. 5 5/7
  3. 5 5/19
  4. 11 1/9

Sol. Solving the mixed fractions to improper fractions; We have, (100/3,100/5,100/7,?,100/11).Assuming, the numerator for the fraction in the place of ? to be 100, we have,(100/3,100/5,100/7,100/x,100/11) ;  Now looking at the denominator the pattern of an increase +2 can be seen, therefore, x= 7+2= 9; Therefore the fraction is ; converting back to mixed fractions – (4) .

 

TYPE-2

Q1.4,9,26, 105, 524, ?

  1. 1524
  2. 3032
  3. 3144
  4. 3145
  5. 3254 

Sol. 4 (x2+1),9 (x3-1), 26 (x 4+1), 105 (x 5-1),524 (x 6 +1), 3145

There are again three different operations in a progressive fashion in the formation of the relationship between the terms. These types of questions require a lot of hit and trial, but it will be visible easily with practice of questions. Answer is (d).

Q2. 8,15,28,53,?

  1. 106
  2. 98
  3. 100
  4. 102

Sol.

 

 

 

 

 

 

Again, there are two operations running simultaneously, even though the product number is same, but the difference is changing with an addition of 1.

Q3. 81, 192, 375, ? ,1029

 

  1. 684
  2. 486
  3. 648
  4. 468
  5. None of these

Soln.  

 

 

 

Now, there are three relationships formed here.

  1. 9+5= 14 +6= 20+7=27+ 8= 35
  2. 0+2=2+3= 5 +4=9+ 5 =14
  • In the solution above, the main equation

These type of questions can only be solved only through practice, if you don’t know that these questions exist you can not attempt or solve these questions without spending a lot of time on it which is definitely not advisable to do while attempting the exam.

 

Code and Relationships

CODING

Technique Alphabet Numbering

A 1 14 N
B 2 15 O
C 3 16 P
D 4 17 Q
E 5 18 R
F 6 19 S
G 7 20 T
H 8 21 U
I 9 22 V
J 10 23 W
K 11 24 X
L 12 25 Y
M 13 26 Z

 

The trick to remember everything is to remember the relation of:  

J Y O T I
10 25 15 20 9

 

Another Variety of questions are as follows:

Q1. In a code, HOSPITALS is coded as HSOLSAPTI. The code of BIOLOGICALS will be

  1. BLICOALIOSG
  2. BOLGICAILOS
  3. SBLAOILOBCG
  4. BSILOALCOIG

Sol.

H O S P I T A L S
H S O L S A P T I

Q2. In certain coding method, the  word  QUESTION is encoded as DOMESTIC. In this coding, what is the code word for the word RESPONSE

    1. OMESUCEM
    2. OMESICSM
    3. OMESICEM
    4. OMESISCM

Sol. 

Q U E S T I O N
D O M E S T I C

 

R E S P O N S E
O M E S I C E M

 

REVERSE ALPHA-NUMBERIC CODING: For these types of questions, one’s left and right should be clear, just joking. But still if one looks at the coding table the division is at N and from N the coding can be reversed too or restarted from 1 or if coding is started from Z then N will probably have the code of M ,is it so? Just check yourself; you will get following result:

 

 

 

 

 

 

For quick calculations, to find an alphabet, following formulas can be used:

  1. 26-N (ODD)
  2. 26-(N-1) (Even)
  3. 26- (14-1) = 26-13= 13

 

These formulas can also be used in seating arrangements, line positioning questions.

Q. Which is the 10th letter to the right of the 8th letter from the left in the reverse order of alphabet series?

  1. H
  2. I
  3. J
  4. B
  5. None of these

Sol :10+8= 18; 26-(18-1) = 9, 9th letter is the answer, which is it?

Q. Which letter will be between the 9th letter from the left and 12th letter from the right?  

  1. K
  2. L
  3. M
  4. N
  5. None of these 

Sol. 9+ 12= 21/2 = 11+1; (( left side number+ right side number)/2 ) +1 = nth number is the position of the required Alphabet.

 

DIRECTIONS

Directions is the oldest but most consistent topic for NET exam. There is always at least one question from this topic. The topic is familiar to everyone, with minimum information required to solve any question but still can be tricky at times. Only practicing and attempting as many questions as possible before the actual exam.

The directions are-

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

1.North.

2.North-East

3.North-West

4.South

5.South- East

6.South-West

7.East

8.West 

  • Angle between N and E is 90 degrees.
  • Angle between NE and E is 45 degrees.
  • Pythagoras theorem is being used = A 2 + B 2 = C 2

 

Q. Suman is 40 mts. south- west of Ashok. Prakash is 40 mts south- east of Ashok. Prakash is in which direction of Suman?     

 

 

 

 

 

 

 

 

 

 

 

Q. Arun started walking from a point P towards north and walk 30 mts, he went to left, walk 40 mts to reach. At what minimum straight-line distance is the point Q from P and in which direction

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

Q. Aman walks 30m towards south then turn to his right, He walks 30m the turn to left and he walks 20m. Again turning to his left and keep walks 30m.How far he is from start point.

 

 

 

 

 

 

 

 

 

 

 

 

 

TIME & DISTANCE

There are three elements in this, Time (t), Speed (s) and Distance (d). The related formulas are:

  • T x s= d
  • S=d/t
  • T=d/s
  • If an Object is stationary and there is a moving bus, train (object) which has length = distance covered = length of the object; that is the distance covered will be the length of the moving object.

TIME and WORK

This is one of the important topics for all the competitive exams. All the exams have at least 1-2 questions from this topic, it includes the variation in the form of Pipes and Cisterns also, most of the students find this portion to be most tricky other than Syllogisms. Teachers and various successful students have mentioned to solve these questions using unitary method or going backwards by using Ration and Proportion and with the help of options.

Some of the important factors related to this topic are as follows:

If A and B are workers and have worked for 10 and 15 days respectively, then,

  • A -10 days; 1-day work of A is 1/10
  • B- 15 days; 1-day work of B is 1/15
  • Total work by A+B together = 1/ (1/10 + 1/15) = 6 days
  • 1-day work of A and B= 1/10 + 1/ 15 = 1/6
  • Total work done = 1

Q. A and B can complete the work in 16 days. If A alone take 24 days to complete the work, then how many days B alone will complete that work.

Sol.  1/A+ 1/B =1/16

         1/A = 1/24

         1/B= 1/16- 1/24= 3-2/48 = 1/48

         B= 48 days, Thus, B will take 48 days.

Q. A completes in 10 days, B in 15 days, alternatively both works, how many days work to complete

  • 1/10 + 1/15 =5/30 =1/6
  • 2 days’ work is 1/6; together they take 6 days to complete work; alternative- 2x 6 =12 days to complete the work.

 

It is very difficult to put all the topics and sub-parts in the form of blogs without any audio or presentation, of course, blogs or a website can never take the place of a book but still, while reading this if you feel if a topic should have been definitely included in this or any element is missing let us know, we will add and will send you everything with full details. Students can also email us for online classes for full Paper-1 course.